5=(-5x^2)-3x-5

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Solution for 5=(-5x^2)-3x-5 equation: 



5=(-5x^2)-3x-5

We move all terms to the left:

5-((-5x^2)-3x-5)=0



We calculate terms in parentheses: -((-5x^2)-3x-5), so:

(-5x^2)-3x-5

We get rid of parentheses

-5x^2-3x-5

Back to the equation:

-(-5x^2-3x-5)



We get rid of parentheses

5x^2+3x+5+5=0

We add all the numbers together, and all the variables

5x^2+3x+10=0

a = 5; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·5·10
Δ = -191
Delta is less than zero, so there is no solution for the equation

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